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Question Number 14291 by Tinkutara last updated on 30/May/17

$$\mathrm{Is}\mathrm{the}\mathrm{equation}\mathrm{correct}\mathrm{for}\mathrm{uniformly}$$$$\mathrm{accelerated}\mathrm{motion}\mathrm{along}\mathrm{a}\mathrm{straight}$$$$\mathrm{line}?$$$$s=vt-\frac{1}{2}{at}^2$$

Commented by tawa tawa last updated on 30/May/17

$$\mathrm{No}....\mathrm{that}\mathrm{is}\mathrm{for}\mathrm{motion}\mathrm{under}\mathrm{gravity}$$

Commented by tawa tawa last updated on 30/May/17

$$\mathrm{it}\mathrm{should}\mathrm{be}+$$

Commented by Tinkutara last updated on 30/May/17

$$\mathrm{But}\mathrm{answer}\mathrm{says}\mathrm{it}\mathrm{is}\mathrm{correct}.\mathrm{I}\mathrm{am}$$$$\mathrm{posting}\mathrm{full}\mathrm{question}.$$

Answered by prakash jain last updated on 30/May/17

$$v=u+at$$$$vt-\frac{1}{2}{at}^2=ut+\frac{1}{2}{at}^2$$

Commented by Tinkutara last updated on 30/May/17

$$\mathrm{Thanks}\mathrm{Sir}!$$

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