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Question Number 143024 by Feruzbek last updated on 09/Jun/21

Answered by bramlexs22 last updated on 09/Jun/21

(1)⇔ 49−x^2 ≤ 24 ⇔ 25 −x^2 ≤0 ⇔ (x+5)(x−5)≥0 ⇔ x≤−5 ∪ x≥5 (2) 49−x^2 > 0 ⇒x^2 −49<0 ⇒−7<x<7 (3)x−2>0⇒x>2 Solution (1)∩(2)∩(3) ⇒ 5≤x<7 or [ 5, 7)

(1)⇔49−x2⩽24⇔25−x2⩽0⇔(x+5)(x−5)⩾0⇔x⩽−5∪x⩾5(2)49−x2>0⇒x2−49<0⇒−7<x<7(3)x−2>0⇒x>2Solution(1)∩(2)∩(3)⇒5⩽x<7or[5,7)

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