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Question Number 143105 by mathdanisur last updated on 10/Jun/21

$$\frac{cos\left(3x\right)}{sin\left(2x\right)}=0$$

Commented by Dwaipayan Shikari last updated on 10/Jun/21

$$cos\left(3x\right)=0$$$$3x=(2k+1)\frac{\pi }{2}\Rightarrow x=(2k+1)\frac{\pi }{6}k\in \mathbb{Z}$$$$sin\left(2x\right)\ne 0$$$$2x\ne g\pi \Rightarrow x\ne \frac{g\pi }{2}$$$$(2k+1)\frac{\pi }{6}\ne \frac{g\pi }{2}\Rightarrow 2k+1\ne 3g\Rightarrow \frac{2k+1}{3}\ne g$$

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