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Question Number 143114 by bounhome last updated on 10/Jun/21

solve: lim_(z→i) ((3z^4 −2z^3 +8z^2 −2z+5)/(z−i))=?

solve:limz→i3z4−2z3+8z2−2z+5z−i=?

Answered by liberty last updated on 10/Jun/21

i^2 =−1; i^3 =−i ;i^4 =1 3z^4 −2z^3 +8z^2 −2z+5 ∣_(z=i) = 3+2i−8−2i+5 = 0 lim_(z→i) ((12z^3 −6z^2 +16z−2)/1) = −12i+6+16i−2=4+4i

i2=−1;i3=−i;i4=13z4−2z3+8z2−2z+5∣z=i=3+2i−8−2i+5=0limz→i12z3−6z2+16z−21=−12i+6+16i−2=4+4i

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