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Question Number 143200 by Guddone last updated on 11/Jun/21

	Answered by Dwaipayan Shikari last updated on 11/Jun/21

	$2 x + 3 y = [\begin{matrix} 2 3 \\ 4 0 \end{matrix}] \Rightarrow 6 x + 9 y = [\begin{matrix} 6 9 \\ 12 0 \end{matrix}] \to (a)$ $3 x + 2 y = [\begin{matrix} 2 - 2 \\ - 1 5 \end{matrix}] \Rightarrow 6 x + 4 y = [\begin{matrix} 4 - 4 \\ - 2 10 \end{matrix}] \to (b)$ $a - b \Rightarrow 5 y = [\begin{matrix} 2 13 \\ 14 - 10 \end{matrix}] \Rightarrow y = [\begin{matrix} \frac{2}{5} \frac{13}{5} \\ \frac{14}{5} - 2 \end{matrix}]$ $x = \frac{1}{2} ([\begin{matrix} 2 3 \\ 4 0 \end{matrix}] - [\begin{matrix} \frac{6}{5} \frac{39}{5} \\ \frac{42}{5} - 6 \end{matrix}]) = \frac{1}{2} ([\begin{matrix} \frac{4}{5} \frac{- 24}{5} \\ \frac{- 22}{5} 6 \end{matrix}]) = [\begin{matrix} \frac{2}{5} - \frac{12}{5} \\ - \frac{11}{5} 3 \end{matrix}]$
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