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Question Number 143240 by cesarL last updated on 11/Jun/21
2y=1x(ay+1)x=2(4a−y)Isequationssystem
Answered by MJS_new last updated on 11/Jun/21
2y=1x(ay+1)⇔2x=a+y⇔x=a+y2⇒2(4a−y)=a+y216a−4y=a+y15a=5yy=3a⇒x=2a
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