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Question Number 143248 by cesarL last updated on 11/Jun/21
∫dxx2−4x+1
Commented by mohammad17 last updated on 11/Jun/21
=∫dx(x−2)2−3=13∫−dx1−(x−23)2=13coth−1(x−23)+C⟨mohammadaldolaimy⟩
Answered by cesarL last updated on 11/Jun/21
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