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Question Number 143252 by bramlexs22 last updated on 12/Jun/21

$$\underset{x\to 0}{\lim }\frac{8x-6x\sin x+\sin 2x}{x^5}=?$$

Answered by Olaf_Thorendsen last updated on 12/Jun/21

$$\frac{8x-6x\sin x+\sin 2x}{x^5}\underset{0}{\sim }\frac{8x-6x^2+2x}{x^5}\underset{0}{\sim }\frac{10}{x^4}\to +\mathrm{\infty }$$

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