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Question Number 143268 by Study last updated on 12/Jun/21

$$li\underset{x\to \mathrm{\infty }}{m}{\left(\frac{x+3}{x-4}\right)}^{-2}=?$$

Answered by SumanKarmakar2007 last updated on 12/Jun/21

$$1$$$$$$

Answered by justtry last updated on 12/Jun/21

$$\frac{lim}{x\to \mathrm{\infty }}\left(\frac{1}{\frac{(x^2+6x+9)\times \frac{1}{x^2}}{(x^2-8x+16)\times \frac{1}{x^2}}}\right)$$$$\frac{1}{\left(\frac{1+0+0}{1-0+0}\right)}=1$$

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