log_(2x+1) (x^2 +1)+log_(x+1) (3(√(2x+5))+18)=2x


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Question Number 143329 by Huy last updated on 13/Jun/21

$\log_{2 x + 1} (x^{2} + 1) + \log_{x + 1} (3 \sqrt{2 x + 5} + 18) = 2 x$
	Answered by Olaf_Thorendsen last updated on 13/Jun/21

	$\log_{2 x + 1} (x^{2} + 1) + \log_{x + 1} (3 \sqrt{2 x + 5} + 18) = 2 x$ $If 2 x + 1 = x^{2} + 1 (x = 2) :$ $\log_{2 x + 1} (x^{2} + 1) = 1$ $\log_{x + 1} (3 \sqrt{2 x + 5} + 18) = \log_{3} 27 = 3$ $2 x = 2 \times 2 = 4$ $x = 2 is a trivial solution$
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