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Question Number 143475 by Ghaniy last updated on 14/Jun/21

$$evaluate;$$$$\frac{{\left(\sqrt{7}\right)}^{\log 64}-{\left(3\right)}^{{\log }_{24}8}}{(\log {}_{2}8-\log {}_{\frac{1}{4}}64)\left(\frac{1}{\log {}_4\left(\frac{1}{64}\right)}\right)}$$

Commented by amin96 last updated on 14/Jun/21

$$super$$

Answered by Ar Brandon last updated on 15/Jun/21

$$\mathrm{\aleph }=\frac{{\left(\sqrt{7}\right)}^{{\log }_{49}64}-{\left(3\right)}^{{\log }_{24}8}}{({\log }_{2}8-{\log }_{\frac{1}{4}}64)\left(\frac{1}{{\log }_4\left(\frac{1}{64}\right)}\right)}$$$$=\frac{7^{\frac{1}{2}\cdot \frac{1}{2}{\log }_{7}64}-3^{{\log }_{24}8}}{(3+3)(-\frac{1}{3})}=-\frac{{64}^{\frac{1}{4}}-3^{{\log }_{24}8}}{2}$$$$=\frac{1}{2}\cdot 3^{{\log }_{24}8}-\sqrt{2}=...$$

Commented by Ghaniy last updated on 15/Jun/21

$$thanks$$

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