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Question Number 143537 by 0731619 last updated on 15/Jun/21

Answered by mr W last updated on 15/Jun/21

((AB+BE)/(BE))=((AD)/(BC))=(a/b) ((AB)/(BE))=((a−b)/b) ((GE)/(AD))=((BE)/(AB))=(b/(a−b)) ⇒GE=((ab)/(a−b)) similarly EH=((ab)/(a−b)) ⇒GH=((2ab)/(a−b))

AB+BEBE=ADBC=abABBE=a−bbGEAD=BEAB=ba−b⇒GE=aba−bsimilarlyEH=aba−b⇒GH=2aba−b

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