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Question Number 143586 by mim24 last updated on 16/Jun/21

Commented by muallim_riyoziyot last updated on 16/Jun/21

$$xaa$$

Answered by bobhans last updated on 16/Jun/21

$$\tan \theta =\mid \frac{-\frac{2}{3}-(-\frac{3}{2})}{1+(-\frac{2}{3})(-\frac{3}{2})}\mid$$$$=\mid \frac{\frac{3}{2}-\frac{2}{3}}{1+1}\mid =\frac{5}{12}$$$$\Rightarrow \theta =\arctan \left(\frac{5}{12}\right)=0.394791$$

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