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Question Number 143630 by Eric002 last updated on 16/Jun/21
provethatifaandcareoddintegersthenab+bcisevenforeveryintegerb?
Commented by mr W last updated on 16/Jun/21
yes.a,c=add⇒a+c=eveneven×anyinteger=even⇒(a+c)b=even
Answered by Rasheed.Sindhi last updated on 16/Jun/21
Leta=2m+1&c=2n+1ab+bc=b(a+c)=b(2m+1+2n+1)=b(2m+2n+2)=2b(m+n+1)(Even)
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