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Question Number 143653 by mim24 last updated on 16/Jun/21

Answered by ajfour last updated on 16/Jun/21

$$x^2-6x-2\sqrt{3}=0$$$$x_1{x}_2=-2\sqrt{3}$$$$x_1+x_2=6$$$$\mid x_1-x_2\mid =\sqrt{36+8\sqrt{3}}$$$$$$

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