Question and Answers Forum

All Questions      Topic List

None Questions

Previous in All Question      Next in All Question      

Previous in None      Next in None      

Question Number 143965 by Khalmohmmad last updated on 20/Jun/21

Commented by Canebulok last updated on 20/Jun/21

Solution:  ⇒ ((log(x))/(log(3))) + ((log(5))/(log(x))) = 0  ⇒ log(x)^2  + log(5)log(3) = 0     Let:  k = log(x)  ⇒ k^2  + log(5)log(3) = 0  By using the quadratic formula:  ⇒ k = ((±(√(−4(log(3)log(5)))))/2)  ⇒ k_1  = + i(√(log(3)log(5)))  ⇒ k_2  = −i(√(log(3)log(5)))     Thus;  ⇒ log(x) = ±i(√(log(3)log(5)))  ⇒ x = 10^(±i(√(log(3)log(5))))      ∼ Kevin

Solution:log(x)log(3)+log(5)log(x)=0log(x)2+log(5)log(3)=0Let:k=log(x)k2+log(5)log(3)=0Byusingthequadraticformula:k=±4(log(3)log(5))2k1=+ilog(3)log(5)k2=ilog(3)log(5)Thus;log(x)=±ilog(3)log(5)x=10±ilog(3)log(5)Kevin

Answered by mr W last updated on 20/Jun/21

((ln x)/(ln 3))+((ln 5)/(ln x))=0  ln x=±i(√(ln 3 ln 5))  x=e^(±i(√(ln 3 ln 5))) =cos (√(ln 3 ln 5))±i sin (√(ln 3 ln 5))

lnxln3+ln5lnx=0lnx=±iln3ln5x=e±iln3ln5=cosln3ln5±isinln3ln5

Terms of Service

Privacy Policy

Contact: info@tinkutara.com