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Question Number 144142 by bobhans last updated on 22/Jun/21
∫cosx+cosx+cosx+cosx+...sinxdx
Answered by liberty last updated on 22/Jun/21
cosx+cosx+cosx+...=ℓcosx+ℓ=ℓ⇒ℓ2−ℓ−cosx=0⇒ℓ=1+1+4cosx2I=∫1+1+4cosx2sinxdx
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