Question and Answers Forum

All Questions      Topic List

Coordinate Geometry Questions

Previous in All Question      Next in All Question      

Previous in Coordinate Geometry      Next in Coordinate Geometry      

Question Number 144210 by bramlexs22 last updated on 23/Jun/21

Answered by liberty last updated on 23/Jun/21

shaded area = (((6+2)/2)).4(√3)−(π/6).36−(π/3).4                = 16(√3)−(π/6)(36+8)                = 16(√3)−((44π)/6) = 16(√3)−((22π)/3)

$$\mathrm{shaded}\:\mathrm{area}\:=\:\left(\frac{\mathrm{6}+\mathrm{2}}{\mathrm{2}}\right).\mathrm{4}\sqrt{\mathrm{3}}−\frac{\pi}{\mathrm{6}}.\mathrm{36}−\frac{\pi}{\mathrm{3}}.\mathrm{4} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:=\:\mathrm{16}\sqrt{\mathrm{3}}−\frac{\pi}{\mathrm{6}}\left(\mathrm{36}+\mathrm{8}\right) \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:=\:\mathrm{16}\sqrt{\mathrm{3}}−\frac{\mathrm{44}\pi}{\mathrm{6}}\:=\:\mathrm{16}\sqrt{\mathrm{3}}−\frac{\mathrm{22}\pi}{\mathrm{3}}\: \\ $$

Terms of Service

Privacy Policy

Contact: info@tinkutara.com