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Question Number 144291 by SOMEDAVONG last updated on 24/Jun/21
Answered by som(math1967) last updated on 24/Jun/21
I=∫02021(2021−x)2021(2021−x)2021+(2021−2021+x)2021dx2I=∫02021x2021+(2021−x)2021x2021+(2021−x)2021dxI=12∫02021dx=12[x]02021=20212∫0af(x)dx=∫0af(a−x)dx
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