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Question Number 144300 by mathdanisur last updated on 24/Jun/21

Answered by Rasheed.Sindhi last updated on 25/Jun/21

(x+1)^(2n+1) −a^(2n+1) =x(x+1)Q(x)+ux+v For x∈Z For x=0 1−a^(2n+1) =v For x=−1 −a^(2n+1) =−u+v −a^(2n+1) =−u+1−a^(2n+1) −u+1=0⇒u=1 R(x)=ux+v=(1)x+1−a^(2n+1) =x+1−a^(2n+1)

(x+1)2n+1−a2n+1=x(x+1)Q(x)+ux+vForx∈ZForx=01−a2n+1=vForx=−1−a2n+1=−u+v−a2n+1=−u+1−a2n+1−u+1=0⇒u=1R(x)=ux+v=(1)x+1−a2n+1=x+1−a2n+1

Commented by mathdanisur last updated on 25/Jun/21

thanks Sir cool

thanksSircool

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