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Question Number 144389 by liberty last updated on 25/Jun/21

 ∫ (x−1)h(x)dx = x^3 −sin 2x+(√(x^2 +1)) + c   ⇒h ′(1)= ?

$$\:\int\:\left(\mathrm{x}−\mathrm{1}\right)\mathrm{h}\left(\mathrm{x}\right)\mathrm{dx}\:=\:\mathrm{x}^{\mathrm{3}} −\mathrm{sin}\:\mathrm{2x}+\sqrt{\mathrm{x}^{\mathrm{2}} +\mathrm{1}}\:+\:\mathrm{c}\: \\ $$$$\Rightarrow\mathrm{h}\:'\left(\mathrm{1}\right)=\:? \\ $$

Answered by mathmax by abdo last updated on 25/Jun/21

h is not ddrivable at x_0 =1  ...!

$$\mathrm{h}\:\mathrm{is}\:\mathrm{not}\:\mathrm{ddrivable}\:\mathrm{at}\:\mathrm{x}_{\mathrm{0}} =\mathrm{1}\:\:...! \\ $$

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