Question and Answers Forum

All Questions      Topic List

None Questions

Previous in All Question      Next in All Question      

Previous in None      Next in None      

Question Number 144403 by SOMEDAVONG last updated on 25/Jun/21

A=lim_(x→0) ((∫_(2x) ^(4x) ((sint)/t)dt)/(e^x −1)) =?

$$\mathrm{A}=\underset{\mathrm{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\frac{\int_{\mathrm{2x}} ^{\mathrm{4x}} \frac{\mathrm{sint}}{\mathrm{t}}\mathrm{dt}}{\mathrm{e}^{\mathrm{x}} −\mathrm{1}}\:=? \\ $$

Answered by imjagoll last updated on 25/Jun/21

 A = lim_(x→0)  ((((sin 4x)/(4x))(4)−((sin 2x)/(2x))(2))/e^x )  A= ((4−2)/1)=2

$$\:\mathrm{A}\:=\:\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\:\frac{\frac{\mathrm{sin}\:\mathrm{4x}}{\mathrm{4x}}\left(\mathrm{4}\right)−\frac{\mathrm{sin}\:\mathrm{2x}}{\mathrm{2x}}\left(\mathrm{2}\right)}{\mathrm{e}^{\mathrm{x}} } \\ $$$$\mathrm{A}=\:\frac{\mathrm{4}−\mathrm{2}}{\mathrm{1}}=\mathrm{2} \\ $$

Terms of Service

Privacy Policy

Contact: info@tinkutara.com