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Question Number 144484 by phally last updated on 25/Jun/21

Answered by Olaf_Thorendsen last updated on 25/Jun/21

S_n  = Σ_(k=1) ^n ((k(k+2))/((k+1)^2 ))  S_n  = Σ_(k=2) ^(n+1) (((k−1)(k+1))/k^2 )  S_n  = Σ_(k=2) ^(n+1) (1−(1/k^2 ))  S_n  = n+1−H_(n+1,2)

$$\mathrm{S}_{{n}} \:=\:\underset{{k}=\mathrm{1}} {\overset{{n}} {\sum}}\frac{{k}\left({k}+\mathrm{2}\right)}{\left({k}+\mathrm{1}\right)^{\mathrm{2}} } \\ $$$$\mathrm{S}_{{n}} \:=\:\underset{{k}=\mathrm{2}} {\overset{{n}+\mathrm{1}} {\sum}}\frac{\left({k}−\mathrm{1}\right)\left({k}+\mathrm{1}\right)}{{k}^{\mathrm{2}} } \\ $$$$\mathrm{S}_{{n}} \:=\:\underset{{k}=\mathrm{2}} {\overset{{n}+\mathrm{1}} {\sum}}\left(\mathrm{1}−\frac{\mathrm{1}}{{k}^{\mathrm{2}} }\right) \\ $$$$\mathrm{S}_{{n}} \:=\:{n}+\mathrm{1}−{H}_{{n}+\mathrm{1},\mathrm{2}} \\ $$

Commented by mnjuly1970 last updated on 26/Jun/21

 divergent...

$$\:{divergent}... \\ $$

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