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Question Number 144517 by Khalmohmmad last updated on 26/Jun/21

Answered by som(math1967) last updated on 26/Jun/21

$$a^4+b^4+2a^2{b}^2-(a^2+b^2)-6=0$$$${(a^2+b^2)}^2-(a^2+b^2)-6=0$$$$x^2-x-6=0[letx=a^2+b^2]$$$$(x-3)(x+2)=0$$$$x=3,-2$$$$\therefore a^2+b^2=3,-2$$

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