A region is enclosed by curves x^2 =4y, x^2 =−4y, x=4 & x=−4 V_1 is the volume of the solid obtained by rotating the above region round the y−axis. Another regions consists of points (x,y) satisfying x^2 +y^2 ≤16, x^2 +(y−2)^2 ≥4 and x^2 +(y+2)^2 ≥4 ,V_2 is the volume of the solid obtained by rotating this region round the y−axis Then V


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Question Number 144771 by imjagoll last updated on 29/Jun/21

$A region is enclosed by curves$ $x^{2} = 4 y, x^{2} = - 4 y, x = 4 & x = - 4$ $V_{1} is the volume of the solid obtained$ $by rotating the above region round$ $the y - axis . Another regions$ $consists of points (x, y) satisfying$ $x^{2} + y^{2} ⩽ 16, x^{2} + {(y - 2)}^{2} ⩾ 4 and$ $x^{2} + {(y + 2)}^{2} ⩾ 4, V_{2} is the volume$ $of the solid obtained by rotating$ $this region round the y - axis$ $Then V_{1} = . . .$
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