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Question Number 144772 by phally last updated on 29/Jun/21
Answered by liberty last updated on 29/Jun/21
limx→1ddx(xx−1)ddx(ln(1−x2−1)considerddx(xx−1)=xx(lnx+1)andddx(ln(1−x2−1))=−xx2−11−x2−1solimx→1xx(lnx−1)(1−x2−1)(x2−1)−x=0
Commented by phally last updated on 29/Jun/21
thankbrother
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