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Question Number 144801 by mohammad17 last updated on 29/Jun/21

if you know that the probability of a picture  appearing when acoin is tossed is 2/5  then the probability of getting writings   when this coin is tossed 6 times ?

$${if}\:{you}\:{know}\:{that}\:{the}\:{probability}\:{of}\:{a}\:{picture} \\ $$$${appearing}\:{when}\:{acoin}\:{is}\:{tossed}\:{is}\:\mathrm{2}/\mathrm{5} \\ $$$${then}\:{the}\:{probability}\:{of}\:{getting}\:{writings}\: \\ $$$${when}\:{this}\:{coin}\:{is}\:{tossed}\:\mathrm{6}\:{times}\:? \\ $$

Commented by mohammad17 last updated on 29/Jun/21

help me sir  ?

$${help}\:{me}\:{sir}\:\:? \\ $$

Commented by mohammad17 last updated on 29/Jun/21

?????????

$$????????? \\ $$

Answered by gsk2684 last updated on 29/Jun/21

X≈B(n,p)  p= prob′ of getting writings   on the coin = (3/5)  q=prob′ of getting picture   on the coin =(2/5)  then p(X≥1)=1−p(X=0)  =1−6_C_0  q^6 p^0 =1−((2/5))^6

$$\mathrm{X}\approx\mathrm{B}\left(\mathrm{n},\mathrm{p}\right) \\ $$$$\mathrm{p}=\:\mathrm{prob}'\:\mathrm{of}\:\mathrm{getting}\:\mathrm{writings}\: \\ $$$$\mathrm{on}\:\mathrm{the}\:\mathrm{coin}\:=\:\frac{\mathrm{3}}{\mathrm{5}} \\ $$$$\mathrm{q}=\mathrm{prob}'\:\mathrm{of}\:\mathrm{getting}\:\mathrm{picture}\: \\ $$$$\mathrm{on}\:\mathrm{the}\:\mathrm{coin}\:=\frac{\mathrm{2}}{\mathrm{5}} \\ $$$$\mathrm{then}\:\mathrm{p}\left(\mathrm{X}\geqslant\mathrm{1}\right)=\mathrm{1}−\mathrm{p}\left(\mathrm{X}=\mathrm{0}\right) \\ $$$$=\mathrm{1}−\mathrm{6}_{\mathrm{C}_{\mathrm{0}} } \mathrm{q}^{\mathrm{6}} \mathrm{p}^{\mathrm{0}} =\mathrm{1}−\left(\frac{\mathrm{2}}{\mathrm{5}}\right)^{\mathrm{6}} \\ $$

Commented by mohammad17 last updated on 29/Jun/21

sir i want the result

$${sir}\:{i}\:{want}\:{the}\:{result}\: \\ $$

Commented by SLVR last updated on 29/Jun/21

very...easy..=15561/15625

$${very}...{easy}..=\mathrm{15561}/\mathrm{15625} \\ $$

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