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Question Number 144888 by imjagoll last updated on 30/Jun/21

Commented by imjagoll last updated on 30/Jun/21

$$\mathrm{find}\mathrm{the}\mathrm{shaded}\mathrm{area}.$$

Answered by nimnim last updated on 30/Jun/21

Commented by mr W last updated on 30/Jun/21

$$howcanyousayBC//AD?$$

Commented by nimnim last updated on 30/Jun/21

$$\mathrm{Ok}.{\mathrm{I}}^{\prime }\mathrm{m}\mathrm{done}.\mathrm{Sir},\mathrm{Please}\mathrm{can}\mathrm{you}\mathrm{show}\mathrm{me}\mathrm{the}\mathrm{correct}\mathrm{way}$$

Answered by mr W last updated on 30/Jun/21

Commented by mr W last updated on 30/Jun/21

$${BC}^2={(4+5)}^2+3^2=90$$$${AC}^2={BC}^2-3^2=81$$$$AC=9$$$$DE=\frac{4}{4+5}\times 3=\frac{4}{3}$$$$EF=\frac{5}{4+5}\times 3=\frac{5}{3}$$$$A_{shade}=\frac{1}{2}\times 9\times 3-\frac{1}{2}\times 4\times \frac{4}{3}+\frac{1}{2}\times 5\times \frac{5}{3}$$$$=15$$

Commented by nimnim last updated on 01/Jul/21

$$\mathrm{Thank}\mathrm{you}\mathrm{Sir}.\mathrm{May}\mathrm{the}\mathrm{good}\mathrm{Lord}\mathrm{bless}\mathrm{you}.$$

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