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Question Number 144900 by ArielVyny last updated on 30/Jun/21

$$etudecompletedelacourbe{d}^{\prime }equation$$$$polairer=\frac{1}{sin\left(2\theta \right)}\left(symetrieettrace\right)$$$$$$

Answered by qaz last updated on 30/Jun/21

$$2\mathrm{rsin}\theta \cos \theta =1$$$$\Rightarrow {2\mathrm{r}}^2\sin \theta \cos \theta =\mathrm{r}$$$$\Rightarrow 2\mathrm{xy}=\sqrt{{\mathrm{x}}^2+{\mathrm{y}}^2}$$$$\Rightarrow {\mathrm{x}}^2+{\mathrm{y}}^2-{4\mathrm{x}}^2{\mathrm{y}}^2=0$$

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