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Question Number 145000 by imjagoll last updated on 01/Jul/21

$$\mathrm{If}\mathrm{F}(\mathrm{x}+1)=\mathrm{F}(\mathrm{x}-1)={\mathrm{x}}^2$$$$\mathrm{then}{\mathrm{F}}^{-1}\left(\mathrm{x}\right)=?$$

Commented by prakash jain last updated on 01/Jul/21

$$f(x+1)=x^2\Rightarrow f\left(x\right)={(x-1)}^2$$$$f(x-1)=x^2\Rightarrow f\left(x\right)={(x+1)}^2$$$$\mathrm{Please}\mathrm{recheck}\mathrm{question}.$$$$f\left(x\right)\mathrm{is}\mathrm{periodic}?$$

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