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Question Number 145057 by 7770 last updated on 02/Jul/21

$$\mathit{f}\mathit{i}\mathit{n}\mathit{d}\mathit{k}\mathit{i}\mathit{f}{\mathit{y}}^2+\mathit{y}+\mathit{k}\mathit{i}\mathit{s}\mathit{a}\mathit{p}\mathit{e}\mathit{r}\mathit{f}\mathit{e}\mathit{c}\mathit{t}$$$$\mathit{s}\mathit{q}\mathit{u}\mathit{a}\mathit{r}\mathit{e}$$

Commented by mr W last updated on 02/Jul/21

$$y^2+y+\frac{1}{4}={(y+\frac{1}{2})}^2$$$$\Rightarrow k=\frac{1}{4}$$

Commented by 7770 last updated on 02/Jul/21

$$\mathit{s}orryits{y}^2+y+kisaperfectsquare$$

Commented by imjagoll last updated on 02/Jul/21

$${\mathrm{y}}^2+\mathrm{y}+\mathrm{k}\to \mathrm{perfect}\mathrm{square}\mathrm{if}△=0$$$$\Rightarrow 1-4\mathrm{k}=0;\mathrm{k}=\frac{1}{4}$$

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