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Question Number 145108 by imjagoll last updated on 02/Jul/21

Answered by liberty last updated on 02/Jul/21

(( ((2^(x+1) /(32^(2x−2) )))^(1/(1/5)) ))^(1/(1/4)) = 64 ⇒ (( ((2^(x+1) /2^(10x−10) ))^5 ))^(1/(1/4)) = 2^6 ⇒(2^(−9x+11) )^(20) = 2^6 ⇒(11−9x)=((10)/3) ⇒9x = ((23)/3) ; x=((23)/(27)).

2x+1322x−21/51/4=64⇒(2x+1210x−10)51/4=26⇒(2−9x+11)20=26⇒(11−9x)=103⇒9x=233;x=2327.

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