we have z = e^(((2pi)/7)i) a = z+ z^2 + z^4 and b = z^3 + z^5 +z^6 we know a + b = −1 and 1−b=a find S = cos(((2pi)/7))+ cos(((4pi)/7)) + cos(((8pi)/7)) thanks for help


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Question Number 145162 by Skabetix last updated on 02/Jul/21

$w e h a v e z = e^{\frac{2 p i}{7} i}$ $a = z + z^{2} + z^{4} a n d b = z^{3} + z^{5} + z^{6}$ $w e k n o w a + b = - 1 a n d 1 - b = a$ $f i n d S = c o s (\frac{2 p i}{7}) + c o s (\frac{4 p i}{7}) + c o s (\frac{8 p i}{7})$ $t h a n k s f o r h e l p$
Commented by gsk2684 last updated on 03/Jul/21

$statements in hypothesis are$ $cotradicts .$
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