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Question Number 145274 by ArielVyny last updated on 03/Jul/21

$${\int }_{\mid z\mid =1}\frac{\stackrel{-}{f}\left(z\right)}{z-a}dz$$

Answered by Olaf_Thorendsen last updated on 03/Jul/21

$$f\left(a\right)=\frac{1}{2\pi i}{\oint }_{\gamma }\frac{f\left(z\right)}{z-a}dz$$$$\mathrm{\Omega }={\int }_{\mid z\mid =1}\frac{\stackrel{\mathrm{\_}}{f}\left(z\right)}{z-a}dz$$$$\mathrm{\Omega }=2\pi i\stackrel{\mathrm{\_}}{f}\left(a\right)$$

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