2^(a!) + 2^(b!) + 2^(c!) = x Find natural numbers a;b;c such that the number “x” is a cube of any number.


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Question Number 145279 by mathdanisur last updated on 03/Jul/21

$2^{a!} + 2^{b!} + 2^{c!} = x$ $F i n d n a t u r a l n u m b e r s a; b; c s u c h$ $t h a t t h e n u m b e r ‘ ‘ x^{″} i s a c u b e o f$ $a n y n u m b e r .$
	Answered by SinNombre last updated on 03/Jul/21

	$h a b l a s e s p a n i o l p o r f a$
	Commented by mathdanisur last updated on 04/Jul/21

	$S i, p o r f a v o r$
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