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Question Number 145337 by physicstutes last updated on 04/Jul/21

$$\mathrm{The}\mathrm{Area}\mathrm{of}\mathrm{a}\mathrm{square},A\left(t\right),\mathrm{is}\mathrm{increased}\mathrm{at}\mathrm{a}\mathrm{rate}$$$$\mathrm{equal}\mathrm{to}\mathrm{its}\mathrm{perimeter},A\left(t\right)\mathrm{satisfies}\mathrm{the}\mathrm{differential}$$$$\mathrm{equation}\frac{dA}{dt}=$$$$\mathrm{A}.4A\mathrm{B}.2A\mathrm{C}.-4\sqrt{A}\mathrm{D}.4\sqrt{A}$$

Answered by gsk2684 last updated on 06/Jul/21

$$\frac{d}{dt}\left(x^2\right)=4x\Rightarrow \frac{dA}{dt}=4\sqrt{A}$$

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