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Question Number 145436 by mathdanisur last updated on 04/Jul/21

Commented by justtry last updated on 05/Jul/21

Commented by mathdanisur last updated on 05/Jul/21

thanks Ser, but wrong  (1+a)^k <=1+ka  if  k∈[0;1]

thanksSer,butwrong(1+a)k<=1+kaifk∈[0;1]

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