x;y;z;t∈Z^+ { ((xy + zt = 38)),((xz + yt = 34)),((xt + yz = 43)) :} ⇒ x+y+z+t=?


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Question Number 145768 by mathdanisur last updated on 07/Jul/21
$x;y;z;t∈Z^+ { ((xy + zt = 38)),((xz + yt = 34)),((xt + yz = 43)) :} ⇒ x+y+z+t=?$
$x; y; z; t \in Z^{+}$ ${\begin{cases} x y + z t = 38 \\ x z + y t = 34 \\ x t + y z = 43 \end{cases} \Rightarrow x + y + z + t = ?$
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