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Question Number 145769 by Engr_Jidda last updated on 07/Jul/21
findxif2x+23x=16
Commented by 7770 last updated on 08/Jul/21
2x+23x=16let2x=mm+m3=16m3+m−16=0letf(x)=m3+m−16f′(x)=3m2+1lettheinitialguessmbe0usingnrim1=m0−f(x)f′(x)m=2.387686553...2x=m2x=2.387686553...x=ln2.387686553...ln2x≈1.255613
Answered by mr W last updated on 07/Jul/21
lett=2xt3+t−16=0Δ=127+64>0Δ=51879⇒t=51879+83−51879−83⇒x=log2(51879+83−51879−83)≈1.255613
Commented by Engr_Jidda last updated on 08/Jul/21
thankyousir
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