a;b;c>0 ; a^2 +b^2 +c^2 =2 prove: (a^6 +b^6 +c^6 )^3 ≥ (a^5 +b^5 +c^5 )^4


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Question Number 145772 by mathdanisur last updated on 07/Jul/21

$a; b; c > 0; a^{2} + b^{2} + c^{2} = 2 p r o v e :$ ${(a^{6} + b^{6} + c^{6})}^{3} ⩾ {(a^{5} + b^{5} + c^{5})}^{4}$
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