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Question Number 145774 by Engr_Jidda last updated on 08/Jul/21

find the area bounded by y=2x, y=(x/2) and?xy=2

findtheareaboundedbyy=2x,y=x2and?xy=2

Answered by ArielVyny last updated on 08/Jul/21

∀x∈R 2x≥(x/2)  A=∫(2x−(x/2))dx=2(1/2)x^2 −(1/2)×(1/2)x^2   A=x^2 −(1/4)x^2 =(3/4)x^2     A=(3/4)x^2   y=2x→yx=2x^2 =2→x=±1  y=(x/2)→yx=(1/2)x^2 =2→x^2 =4→x=±2  then xy=2 solutions are incompatibles

xR2xx2A=(2xx2)dx=212x212×12x2A=x214x2=34x2A=34x2y=2xyx=2x2=2x=±1y=x2yx=12x2=2x2=4x=±2thenxy=2solutionsareincompatibles

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