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Question Number 146076 by Mrsof last updated on 10/Jul/21

$$iff\left(x\right)=\int (3x^2-2)dxandf\left(2\right)=9then$$$$f(-2)=?$$

Answered by gsk2684 last updated on 10/Jul/21

$$f\left(x\right)=x^3-2x+c$$$$f\left(2\right)=9\Rightarrow 8-4+c=9$$$$\therefore f(-2)=-8+4+5$$

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