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Question Number 146096 by mathdanisur last updated on 10/Jul/21

Answered by mindispower last updated on 10/Jul/21

$$tg\left(2a\right)=tg(a+b+a-b)=\frac{tg(a+b)+tg(a-b)}{1-tg(a+b)tg(a-b)}=\frac{\frac{3}{2}}{\frac{1}{2}}$$$$=3\Rightarrow 2tg\left(2a\right)=6$$

Commented by mathdanisur last updated on 11/Jul/21

$$cool,thanksSer$$

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