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Question Number 146155 by mnjuly1970 last updated on 11/Jul/21

$$$$$${lim}_{n\to \mathrm{\infty }}{\left(Arcsin\left(x\right)\right)}^n=0$$$$\therefore x\in ?$$$$Q:mrliberty$$$$$$

Commented by mathmax by abdo last updated on 11/Jul/21

$$\Rightarrow -1<\mathrm{arcsinx}<1\Rightarrow -\frac{\pi }{2}<\mathrm{x}<\frac{\pi }{2}$$

Commented by mnjuly1970 last updated on 12/Jul/21

$$x=\frac{\pi -\frac{1}{2}}{2}\Rightarrow arcsin(\frac{\pi -\frac{1}{2}}{2}>1)=?$$

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