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Question Number 146158 by aliibrahim1 last updated on 11/Jul/21

Commented by MJS_new last updated on 12/Jul/21

$$x^2+y^2=z$$$$z=10\vee z=10(-\frac{1}{2}\pm \frac{\sqrt{3}}{2}\mathrm{i})$$

Answered by mnjuly1970 last updated on 11/Jul/21

$$i:x^6-6x^4{y}^2+9x^2{y}^4=900$$$$ii:y^6-6y^4{x}^2+9y^2{x}^4=100$$$$i+ii:x^6+3x^2{y}^4+3x^4{y}^2+y^6=1000$$$${(x^2+y^2)}^3=1000$$$$x^2+y^2=10....$$

Commented by aliibrahim1 last updated on 11/Jul/21

$$thxsir$$

Commented by mnjuly1970 last updated on 11/Jul/21

$$youarewelcom...$$

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