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Question Number 148339 by mathdanisur last updated on 27/Jul/21

$$arccos\left(cos9\right)=?$$

Answered by Olaf_Thorendsen last updated on 27/Jul/21

$$x=\arccos \left(\cos 9\right))$$$$x=\arccos \left(\cos (9-2\pi )\right)),9-2\pi \in [0,\pi ]$$$$x=9-2\pi$$

Commented by mathdanisur last updated on 27/Jul/21

$$ThankyouSir$$

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