Question and Answers Forum

All Questions      Topic List

None Questions

Previous in All Question      Next in All Question      

Previous in None      Next in None      

Question Number 146528 by 0731619 last updated on 13/Jul/21

Answered by Olaf_Thorendsen last updated on 14/Jul/21

$$\mathrm{Let}x=6+ϵ$$$$\frac{x!!-48}{6-\sqrt{6x}}=\frac{(6+ϵ)(4+ϵ)(2+ϵ)-48}{6-\sqrt{6(6+ϵ)}}$$$$=\frac{44ϵ+12{ϵ}^2+{ϵ}^3}{6-6(1+\frac{1}{2}.\frac{ϵ}{6})}\underset{ϵ\to 0}{\sim }-88$$

Terms of Service

Privacy Policy

Contact: info@tinkutara.com