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Question Number 146590 by tabata last updated on 14/Jul/21

Commented by tabata last updated on 14/Jul/21

$$helpmesir$$

Answered by physicstutes last updated on 14/Jul/21

$$1.{\mathrm{CH}}_3{\mathrm{CH}}_2\mathrm{MgCl}\underset{\mathrm{dil}\mathrm{HCl}}{\to }{\mathrm{CH}}_3{\mathrm{CH}}_2{\mathrm{CH}}_2{\mathrm{CH}}_3$$$$2.{\mathrm{CH}}_3{\mathrm{CH}}_2{\mathrm{CH}}_2{\mathrm{CH}}_2\mathrm{OH}\underset{\mathrm{conc}{\mathrm{H}}_2{\mathrm{SO}}_4}{\to }{\mathrm{CH}}_3{\mathrm{CH}}_2\mathrm{CH}={\mathrm{CH}}_2\left(\mathrm{using}{\mathrm{Al}}_2{\mathrm{O}}_3\mathrm{also}\mathrm{works}\right)$$$$3.{\mathrm{CH}}_3{\mathrm{CH}}_2{\mathrm{CH}}_2\mathrm{OH}\underset{{\mathrm{Al}}_2{\mathrm{O}}_3/\mathrm{heat}}{\to }{\mathrm{CH}}_3\mathrm{CH}={\mathrm{CH}}_2$$

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