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Question Number 14661 by ajfour last updated on 03/Jun/17

Commented by ajfour last updated on 03/Jun/17

$$\mathit{P}\mathit{r}\mathit{o}\mathit{v}\mathit{e}\mathit{P}\mathit{y}\mathit{t}\mathit{h}\mathit{a}\mathit{g}\mathit{o}\mathit{r}\mathit{a}\mathit{s}\mathit{t}\mathit{h}\mathit{e}\mathit{o}\mathit{r}\mathit{e}\mathit{m}$$$$withtheaidofimageabove.$$

Answered by b.e.h.i.8.3.4.1.7@gmail.com last updated on 03/Jun/17

$$h^2=4\times \frac{1}{2}bp+{(b-p)}^2=b^2+p^2.◼$$

Commented by ajfour last updated on 03/Jun/17

$$hownice,youwer\mathit{e}\mathit{q}uick!$$

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