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Question Number 146764 by Ar Brandon last updated on 15/Jul/21

$$\mathrm{A}={(\frac{(\mathrm{x}+\sqrt[3]{{2\mathrm{ax}}^2}){(2\mathrm{a}+\sqrt[3]{{2\mathrm{a}}^2\mathrm{x}})}^{-1}-1}{\sqrt[3]{\mathrm{x}}-\sqrt[3]{2\mathrm{a}}}-{\left(2\mathrm{a}\right)}^{-1/3})}^{-6},(\mathrm{a},\mathrm{b})\in {\mathbb{R}}^2$$$$\mathrm{a}-\mathrm{A}=\frac{{16\mathrm{a}}^4}{{\mathrm{x}}^2}\mathrm{b}-\mathrm{A}=\frac{8}{\mathrm{ax}}\mathrm{c}-\mathrm{A}=\frac{\sqrt[3]{2\mathrm{a}}}{{3\mathrm{x}}^3}$$

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